DateDiff Function

Returns the number of date or time intervals between two given date values.

Syntax:


DateDiff (interval As String, date1 As Date, date2 As Date [, firstDayOfWeek As Integer [, firstWeekOfYear As Integer]]) As Double

Qolote guma:

Kiiro.

Parameters:

interval - A string expression from the following table, specifying the date or time interval.

interval (string value)

Tittirsha

yyyy

Diro

b

Bocuboco

a

Agana

d

Diri barra

l

Loosubarruwa

ll

Diri lamala

b

Barra

y

Saate

d

Daqiiqa

s

Sakonde


date1, date2 - The two date values to be compared.

Date literals allow to specify unambiguous date variables that are independent from the current language. Literals are enclosed between hash signs #. Possible formats are:

firstdayofweek: An optional parameter that specifies the starting day of a week.

firstdayofweek value

Xawishsha

0

Amuraatu gadimmate guma horonsi'ri

1

Sambata(gadimma)

2

Sanyo

3

Masanyo

4

Roowe

5

Hamuse

6

Arbe

7

Qidaame


firstweekofyear: An optional parameter that specifies the starting week of a year.

firstweekofyear value

Xawishsha

0

Amuraatu gadimma guma horonsiri

1

Lamala 1 arfaasa lamalaati, 1ha (gade)

2

Lamala 1 dirunnita shoole woy shoolete ale barruwa amaddanno umi lamalaati

3

Lamala 1 haaru diri barruwa calla amadanno umi lamalaati


Example:


Sub example_datediff
    MsgBox DateDiff("d", #1/1/2005#, #2005-12-31#)
End Sub

Please support us!