DateDiff Function

Returns the number of date or time intervals between two given date values.

Syntax:


DateDiff (interval As String, date1 As Date, date2 As Date [, firstDayOfWeek As Integer [, firstWeekOfYear As Integer]]) As Double

Qolote guma:

Kiiro.

Parameters:

interval - A string expression from the following table, specifying the date or time interval.

interval (string value)	Tittirsha
yyyy	Diro
q	Bocuboco
m	Agana
y	Diri barra
w	Loosubarruwa
ww	Diri lamala
d	Barra
h	Saate
n	Daqiiqa
s	Sakonde

date1, date2 - The two date values to be compared.

Date literals allow to specify unambiguous date variables that are independent from the current language. Literals are enclosed between hash signs #. Possible formats are:

#yyyy-mm-dd#
#mm/dd/yyyy#

firstdayofweek: An optional parameter that specifies the starting day of a week.

firstdayofweek value	Xawishsha
0	Amuraatu gadimmate guma horonsi'ri
1	Sambata(gadimma)
2	Sanyo
3	Masanyo
4	Roowe
5	Hamuse
6	Arbe
7	Qidaame

firstweekofyear: An optional parameter that specifies the starting week of a year.

firstweekofyear value	Xawishsha
0	Amuraatu gadimma guma horonsiri
1	Lamala 1 arfaasa lamalaati, 1ha (gade)
2	Lamala 1 dirunnita shoole woy shoolete ale barruwa amaddanno umi lamalaati
3	Lamala 1 haaru diri barruwa calla amadanno umi lamalaati

Example:


Sub example_datediff
    MsgBox DateDiff("d", #1/1/2005#, #2005-12-31#)
End Sub