DatePart Function

DatePart āˇāˇŠâ€āļģāˇ’āļ­āļē āļąāˇ’āļēāļ¸āˇ’āļ­ āļ¯āˇ’āļąāļēāļš āļąāˇ’āļēāļ¸āˇ’āļ­ āļšāˇœāļ§āˇƒāļšāˇŠ āļŊāļļāˇ āļ¯āˇš.

Syntax:


DatePart (interval As String, date As Date [, firstDayOfWeek As Integer [, firstWeekOfYear As Integer]]) As Long

āļ†āļ´āˇƒāˇ” āļŊāļļāˇāļ¯āˇ™āļą āļ…āļœāļē:

The extracted part for the given date.

Parameters:

interval - A string expression from the following table, specifying the date interval.

interval (string value)

āˇ€āˇ’āˇƒāˇŠāļ­āļģ āļšāˇ’āļģāˇ“āļ¸

yyyy

Year

q

Quarter

m

Month

y

Day of year

w

Weekday

ww

Week of year

d

Day

h

Hour

n

Minute

s

Second


date - The date from which the result is calculated.

Date literals allow to specify unambiguous date variables that are independent from the current language. Literals are enclosed between hash signs #. Possible formats are:

firstdayofweek: An optional parameter that specifies the starting day of a week.

firstdayofweek value

āˇ€āˇ’āˇƒāˇŠāļ­āļģ āļšāˇ’āļģāˇ“āļ¸

0

Use system default value

1

Sunday (default)

2

Monday

3

Tuesday

4

Wednesday

5

Thursday

6

Friday

7

Saturday


firstweekofyear: An optional parameter that specifies the starting week of a year.

firstweekofyear value

āˇ€āˇ’āˇƒāˇŠāļ­āļģ āļšāˇ’āļģāˇ“āļ¸

0

Use system default value

1

Week 1 is the week with January, 1st (default)

2

Week 1 is the first week containing four or more days of that year

3

Week 1 is the first week containing only days of the new year


Example:


Sub example_datepart
    MsgBox DatePart("ww", #12/31/2005#)
    MsgBox DatePart(date:=#1999-12-30#, interval:="q")
End Sub

Please support us!