DateDiff Function

Returns the number of date or time intervals between two given date values.

Syntax:


DateDiff (interval As String, date1 As Date, date2 As Date [, firstDayOfWeek As Integer [, firstWeekOfYear As Integer]]) As Double

Gatii deebii:

Lakkoofsi

Parameters:

interval - A string expression from the following table, specifying the date or time interval.

interval (string value)	Ibsa
yyyy	Waggaa
q	Kumaana
m	Ji'a
y	Guyyaa Waggaa
w	Guyyaa Torbee
ww	Torbee Waggaa
d	Guyyaa
h	Sa'aa
n	Daqiiqaa
s	Sekandii

date1, date2 - The two date values to be compared.

Date literals allow to specify unambiguous date variables that are independent from the current language. Literals are enclosed between hash signs #. Possible formats are:

#yyyy-mm-dd#
#mm/dd/yyyy#

firstdayofweek: An optional parameter that specifies the starting day of a week.

firstdayofweek value	Ibsa
0	Gatii sirna Durtii fayyadami
1	Dilbata(Duurtii)
2	Wixata
3	Kibxata
4	Roobii
5	Kamisa
6	Jimaata
7	Sanbata

firstweekofyear: An optional parameter that specifies the starting week of a year.

firstweekofyear value	Ibsa
0	Gatii sirna Durtii fayyadami
1	Torbeen 1 torbee Amajjii waliin, 1st(durtii)
2	Torbeen 1 torbee tokkoffaa guyyoota bara sanaa afur ykn isaa ol kan of keessaa qabu
3	Torbeen 1 torbee tokkoffaa guyyoota waggaa haraa qofa of keessaa qabu

Example:


Sub example_datediff
    MsgBox DateDiff("d", #1/1/2005#, #2005-12-31#)
End Sub