DatePart Function

The DatePart function returns a specified part of a date.

Syntax:


DatePart (interval As String, date As Date [, firstDayOfWeek As Integer [, firstWeekOfYear As Integer]]) As Long

Врати вредност:

The extracted part for the given date.

Parameters:

interval - A string expression from the following table, specifying the date interval.

interval (string value)

Explanation

yyyy

Year

q

Quarter

m

Month

y

Day of year

w

Weekday

ww

Week of year

d

Day

h

Hour

n

Minute

s

Second


date - The date from which the result is calculated.

Date literals allow to specify unambiguous date variables that are independent from the current language. Literals are enclosed between hash signs #. Possible formats are:

firstdayofweek: An optional parameter that specifies the starting day of a week.

firstdayofweek value

Explanation

0

Use system default value

1

Sunday (default)

2

Monday

3

Tuesday

4

Wednesday

5

Thursday

6

Friday

7

Saturday


firstweekofyear: An optional parameter that specifies the starting week of a year.

firstweekofyear value

Explanation

0

Use system default value

1

Week 1 is the week with January, 1st (default)

2

Week 1 is the first week containing four or more days of that year

3

Week 1 is the first week containing only days of the new year


Example:


Sub example_datepart
    MsgBox DatePart("ww", #01/02/2005#) ' displays 2 because weeks start on Sunday
    MsgBox DatePart("ww", #12/31/2005#) ' displays 53
    MsgBox DatePart(date:=#2005-12-30#, interval:="q") ' displays 4
End Sub

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