DateDiff Function

Returns the number of date intervals between two given date values.

Syntax:


DateDiff (Add, Date1, Date2 [, Week_start [, Year_start]])

Return value:

A number.

Parameters:

Add - A string expression from the following table, specifying the date interval.

Add (string value)

Explanation

yyyy

Year

q

Quarter

m

Month

y

Day of year

w

Weekday

ww

Week of year

d

Day

h

Hour

n

Minute

s

Second


Date1, Date2 - The two date values to be compared.

Week_start - An optional parameter that specifies the starting day of a week.

Week_start value

Explanation

0

Use system default value

1

Sunday (default)

2

Monday

3

Tuesday

4

Wednesday

5

Thursday

6

Friday

7

Saturday


Year_start - An optional parameter that specifies the starting week of a year.

Year_start value

Explanation

0

Use system default value

1

Week 1 is the week with January, 1st (default)

2

Week 1 is the first week containing four or more days of that year

3

Week 1 is the first week containing only days of the new year


Example:


Sub example_datediff
    MsgBox DateDiff("d", "1/1/2005", "12/31/2005")
End Sub

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