MONTH

Returns the hyperbolic cosine of a complex number. The hyperbolic cosine of a complex number can be expressed by:

cosh(a+bi)=cosh(a)cos(b)+sinh(a)sin(b)i

The result is presented in the string format and has the character "i" or "j" as an imaginary unit.

แƒจแƒ”แƒœแƒ˜แƒจแƒ•แƒœแƒ˜แƒก แƒฎแƒแƒขแƒฃแƒšแƒ

This function is part of the Open Document Format for Office Applications (OpenDocument) standard Version 1.2. (ISO/IEC 26300:2-2015)


tip

This function is available since LibreOffice 3.6


แƒกแƒ˜แƒœแƒขแƒแƒฅแƒกแƒ˜

IMCOS(แƒ™แƒแƒ›แƒžแƒšแƒ”แƒฅแƒกแƒฃแƒ แƒ˜ แƒ แƒ˜แƒชแƒฎแƒ•แƒ˜)

Complex_number is a complex number whose hyperbolic cosine is to be calculated.

แƒจแƒ”แƒœแƒ˜แƒจแƒ•แƒœแƒ˜แƒก แƒฎแƒแƒขแƒฃแƒšแƒ

A complex number is a string expression resulting in the form "a+bi" or "a+bj", where a and b are numbers.
If the complex number is actually a real number (b=0), then it can be either a string expression or a number value.


แƒ’แƒแƒ•แƒ แƒ—แƒฎแƒ˜แƒšแƒ”แƒ‘แƒ˜แƒก แƒฎแƒแƒขแƒฃแƒšแƒ

The function always returns a string representing a complex number.
If the result is a complex number with one of its parts (a or b) equal to zero, that part is not displayed.


แƒ›แƒแƒ’แƒแƒšแƒ˜แƒ—แƒ”แƒ‘แƒ˜

=IMCOSH("4-3i")
returns -27.0349456030742-3.85115333481178i.

=IMCOSH(2)
returns 3.76219569108363 as a string. The imaginary part is equal to zero, so it is not displayed in the result.

Open file with example:

[text/scalc/01/func_imcos.xhp#imcos_head not found]., [text/scalc/01/func_imsin.xhp#imsin_head not found]., [text/scalc/01/func_imsinh.xhp#imsinh_head not found].

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