Left Function

Returns the number of leftmost characters that you specify of a string expression.

Syntax:


Left (string As String, length As Long) As String

Return value:

แƒกแƒขแƒ แƒ˜แƒฅแƒแƒœแƒ”แƒ‘แƒ˜

Parameters:

string: Any string expression that you want to return the leftmost characters from.

length: Numeric expression that specifies the number of characters that you want to return. If length = 0, a zero-length string is returned. The maximum allowed value is 2,147,483,648.

แƒจแƒ”แƒ›แƒ“แƒ”แƒ’แƒ˜ แƒ›แƒแƒ’แƒแƒšแƒ˜แƒ— แƒ˜ แƒ’แƒแƒ แƒ“แƒแƒฅแƒ›แƒœแƒ˜แƒก แƒ—แƒแƒ แƒ˜แƒฆแƒก แƒคแƒแƒ แƒ›แƒแƒขแƒจแƒ˜ YYYY.MM.DD แƒคแƒแƒ แƒ›แƒแƒขแƒก MM/DD/YYYY แƒคแƒแƒ แƒ›แƒแƒขแƒจแƒ˜.

Error codes:

D'oh! You found a bug (text/sbasic/shared/00000003.xhp#err5 not found).

Example:


Sub ExampleUSDate
Dim sInput As String
Dim sUS_date As String
    sInput = InputBox("Please input a date in the international format 'YYYY-MM-DD'")
    sUS_date = Mid(sInput, 6, 2)
    sUS_date = sUS_date & "/"
    sUS_date = sUS_date & Right(sInput, 2)
    sUS_date = sUS_date & "/"
    sUS_date = sUS_date & Left(sInput, 4)
    MsgBox sUS_date
End Sub

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