MIDB

Mengembalikan untai teks dari teks DBCS. Parameter menentukan posisi awal dan nomor karakter.

tip

Fungsi ini tersedia sejak LibreOffice 4.2.


Sintaksis

MIDB("Teks"; Mulai; Nomor_bita)

Teks adalah teks yang berisi karakter yang diekstrak.

Mulai adalah posisi pertama karakter dalam teks yang diekstrak.

Nomor_bita menentukan jumlah karakter yang akan dikembalikan dari teks, dalam bita.

Contoh

=MIDB("中国";1;0) returns "" (0 bytes is always an empty string).

=MIDB("中国";1;1) returns " " (1 byte is only half a DBCS character and therefore the result is a space character).

=MIDB("中国";1;2) returns "中" (2 bytes constitute one complete DBCS character).

=MIDB("中国";1;3) returns "中 " (3 bytes constitute one and a half DBCS character; the last byte results in a space character).

=MIDB("中国";1;4) returns "中国" (4 bytes constitute two complete DBCS characters).

=MIDB("中国";2;1) returns " " (byte position 2 is not at the beginning of a character in a DBCS string; 1 space character is returned).

=MIDB("中国";2;2) returns " " (byte position 2 points to the last half of the first character in the DBCS string; the 2 bytes asked for therefore constitutes the last half of the first character and the first half of the second character in the string; 2 space characters are therefore returned).

=MIDB("中国";2;3) returns " 国" (byte position 2 is not at the beginning of a character in a DBCS string; a space character is returned for byte position 2).

=MIDB("中国";3;1) returns " " (byte position 3 is at the beginning of a character in a DBCS string, but 1 byte is only half a DBCS character and a space character is therefore returned instead).

=MIDB("中国";3;2) returns "国" (byte position 3 is at the beginning of a character in a DBCS string, and 2 bytes constitute one DBCS character).

=MIDB("office";2;3) returns "ffi" (byte position 2 is at the beginning of a character in a non-DBCS string, and 3 bytes of a non-DBCS string constitute 3 characters).

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