DDB Function [VBA]

Returns the depreciation of an asset for a specified period using the arithmetic-declining method.

This constant, function or object is enabled with the statement Option VBASupport 1 placed before the executable program code in a module.

DDB(Cost As Double, Salvage As Double, Life as Double, Period as Double, [Factor as Variant])

Double

\<emph\>Cost\</emph\> fixes the initial cost of an asset.

\<emph\>Salvage\</emph\> fixes the value of an asset at the end of its life.

\<emph\>Life\</emph\> is the number of periods defining how long the asset is to be used.

\<emph\>Period\</emph\> defines the length of the period. The length must be entered in the same time unit as life.

\<emph\>Factor\</emph\> (optional) is the factor by which depreciation decreases. If a value is not entered, the default is factor 2.

Use this form of depreciation if you require a higher initial depreciation value as opposed to linear depreciation. The depreciation value gets less with each period and is usually used for assets whose value loss is higher shortly after purchase (for example, vehicles, computers). Please note that the book value will never reach zero under this calculation type.

Sub ExampleDDB
 Dim ddb_yr1 As Double
 ddb_yr1 = DDB(75000,1,60,12,2)
 Print ddb_yr1 ' returns 1,721.81 currency units.
End Sub