DateDiff Function

Returns the number of date or time intervals between two given date values.

DateDiff (interval As String, date1 As Date, date2 As Date [, firstDayOfWeek As Integer [, firstWeekOfYear As Integer]]) As Double

ཕྱིར་ལོག་ཐང་

གྲངས་ཀ་

interval - A string expression from the following table, specifying the date or time interval.

date1, date2 - The two date values to be compared.

firstdayofweek: An optional parameter that specifies the starting day of a week.

firstweekofyear: An optional parameter that specifies the starting week of a year.

Sub example_datediff
    MsgBox DateDiff("d", #1/1/2005#, #2005-12-31#)
End Sub