The DatePart function returns a specified part of a date.
Syntax:
DatePart (interval As String, date As Date [, firstDayOfWeek As Integer [, firstWeekOfYear As Integer]]) As Long
Return value:
The extracted part for the given date.
Parameters:
interval - A string expression from the following table, specifying the date interval.
interval (string value)
Explanation
yyyy
السنة
q
ربع السنة
m
الشهر
y
Day of year
w
Weekday
ww
Week of year
d
اليوم
h
الساعة
n
الدقيقة
s
ثانية
date - The date from which the result is calculated.
Date literals allow to specify unambiguous date variables that are independent from the current language. Literals are enclosed between hash signs #. Possible formats are:
#yyyy-mm-dd#
#mm/dd/yyyy#
firstdayofweek: An optional parameter that specifies the starting day of a week.
firstdayofweek value
Explanation
0
Use system default value
1
Sunday (default)
2
Monday
3
Tuesday
4
Wednesday
5
Thursday
6
Friday
7
Saturday
firstweekofyear: An optional parameter that specifies the starting week of a year.
firstweekofyear value
Explanation
0
Use system default value
1
Week 1 is the week with January, 1st (default)
2
Week 1 is the first week containing four or more days of that year
3
Week 1 is the first week containing only days of the new year
Example:
Sub example_datepart
MsgBox DatePart("ww", #01/02/2005#) ' displays 2 because weeks start on Sunday
MsgBox DatePart("ww", #12/31/2005#) ' displays 53
MsgBox DatePart(date:=#2005-12-30#, interval:="q") ' displays 4
End Sub